back to root
back to new members
2019-04-03 16:37:42 (GMT)
test
2019-06-18 14:15:22 (GMT)
Test 1 2 ...
2019-08-15 15:42:31 (GMT)
Test this: a≠b∧∑ixi a \neq b \land \sum_i x^i a=b∧∑ixi
and:
f(0)=0f(x)=x⋅f(x−1)f(0) = 0 \\ f(x) = x \cdot f(x-1)f(0)=0f(x)=x⋅f(x−1)